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Configuration = 29
cycles = (10 7 3 8 5)(9 4 1 6 2)

a = 4, b = 6, c = 9
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cycles = (10 5 3 6 8)(9 2)(7)(4 1)

a = 5, b = 8, c = 10
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cycles = (10)(9)(8 5 3)(7)(6 2)(4 1)

a = 1, b = 2, c = 6
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cycles = (10)(9)(8 4 2)(7)(6)(5 1 3)

a = 1, b = 3, c = 5
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cycles = (10)(9)(8 2 4)(7)(6)(5)(3)(1)